((5x+1)/4)-((2x-1)/2)=x^2

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Solution for ((5x+1)/4)-((2x-1)/2)=x^2 equation: 



((5x+1)/4)-((2x-1)/2)=x^2

We move all terms to the left:

((5x+1)/4)-((2x-1)/2)-(x^2)=0

determiningTheFunctionDomain
-x^2+((5x+1)/4)-((2x-1)/2)=0

We add all the numbers together, and all the variables

-1x^2+((5x+1)/4)-((2x-1)/2)=0

We calculate fractions


-1x^2+(10x+2)/()+(-8x+4)/()=0

We multiply all the terms by the denominator


-1x^2*()+(10x+2)+(-8x+4)=0

We get rid of parentheses

-1x^2*()+10x-8x+2+4=0

We add all the numbers together, and all the variables

-1x^2*()+2x+6=0

We move all terms containing x to the left, all other terms to the right

-1x^2*()+2x=-6

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